If y^5 + 3(x^2)(y^2) + 5x^4 = 49 , then dy/dx at the point (–1, 2) is?
I have no clue how to start this problem, could someone explain it to me?
Start by using the product rule and the chain rule
y^5 + 3(x^2)(y^2) + 5x^4 = 49
5y^4 y' + 3[(2x)(y^2)+(x^2)(2yy')] + 20x^3 = 0
Now collect all the y' terms, divide, and plug in your numbers.