A balloon rubbed against denim gains a charge of -8.45µC. What is the electric force between the balloon and the denim when the two are separated by a distance of 4.7cm? (Assume the charges are located at a point)

the charge gained by the balloon is lost by the denim

so you have two opposite charges of known size, and you know the distance between them

google "electrostatic force equation"

i need help with this

A Formula something

thank you

To find the electric force between two charged objects, we can use Coulomb's Law formula:

Electric force (F) = (k * q1 * q2) / r^2

Where:
- F is the electric force
- k is Coulomb's constant (9 x 10^9 N m^2/C^2)
- q1 and q2 are the charges of the two objects
- r is the distance between the charges

In this case, the charge of the balloon is -8.45µC (microCoulombs), and we assume the charge of the denim is positive (+8.45µC) since the charges created by rubbing are of opposite signs. The distance between them is 4.7cm, which we need to convert to meters (m).

First, let's convert the distance from centimeters to meters:
4.7cm = 4.7 * 0.01m = 0.047m

Now we can substitute the given values into the formula:
F = (9 x 10^9 N m^2/C^2) * (-8.45 x 10^(-6) C) * (8.45 x 10^(-6) C) / (0.047m)^2

Calculating each part of the formula:

(-8.45 x 10^(-6) C) * (8.45 x 10^(-6) C) = -71.4025 x 10^(-12) C^2

(0.047m)^2 = 0.002209m^2

Now we can substitute the values into the formula and calculate the electric force:
F = (9 x 10^9 N m^2/C^2) * ( -71.4025 x 10^(-12) C^2) / 0.002209m^2

F = -32340648.77 N
(Rounded to the nearest whole number)

Therefore, the electric force between the balloon and the denim is approximately -3.23 x 10^7 N.