A force of 10N acts east and second force 5N acts northward.The resultant force is
|F|sqrt (125)
tan of angle north of east = 5/10 = .5
angle = 26.6 deg
(math angle above east axis)
tan of angle east of north = 90 - above angle
(navigator's compass angle east of north)
To find the resultant force, we need to combine the individual forces using vector addition. This can be done by forming a right-angled triangle with the forces as its sides. The hypotenuse will represent the resultant force.
Here's how you can calculate the resultant force using these steps:
1. Draw a diagram representing the forces. Draw one arrow pointing east representing the 10N force and another arrow pointing north representing the 5N force.
N (5N)
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W---+---E (10N)
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S
2. Create a right-angled triangle using the two forces as the sides. The eastward force (10N) will be the base of the triangle, and the northward force (5N) will be the perpendicular side.
N (5N)
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| /|
W---+---E (10N)
| /
|/
S
3. Apply Pythagoras' theorem to find the length of the hypotenuse, which represents the resultant force.
Resultant force^2 = (10N)^2 + (5N)^2
Resultant force^2 = 100N^2 + 25N^2
Resultant force^2 = 125N^2
Resultant force = √125N^2
Resultant force ≈ 11.18N
Therefore, the magnitude of the resultant force is approximately 11.18N. The direction of the force can be found by taking the inverse tangent of the ratio of the northward force to the eastward force. In this case, it would be the inverse tangent of (5N / 10N), which equals 26.57 degrees north of east.