math

Solve the problem by making up an equation. A child is 12 years old, and his father is 32 years older. In how many years will the age of the father be 3 times the age of the child?
Just tell me the equation.

asked by john
  1. y = 12 years
    Child = y
    Father = y + 32
    Year of Father = x
    Year difference = z

    3x = y + 3(y + 32)
    3x = 12 + 3(12 + 32)
    3x = 144
    x = 48
    - - - - - - - - - -

    z = x - (y + 32)
    z = 48 - (12 + 32)
    z = 48 - 44
    z = 4

    In 4 years, the age of the father will be 3 times the age of the child.

    posted by Anonymous
  2. post it.

    posted by Henry
  3. z = ((y + 3(y+32)) / 3) - (y + 32)

    posted by Anonymous

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