A bag contains:

5 red marbles
6 blue marbles
3 green marbles
4 black marbles
2 yellow marbles

A marble will be drawn from the bag and replaced 100 times. What is the reasonable prediction for the number of times a green or black marble will be drawn?

It is 35

green or black:

Pr(green or black)=(3+4)/20
number in 100 times= 7/20 * 100

the teacher does not even give the answer!

thank u

A bag contains:

• 5 red marbles
• 6 blue marbles
• 3 green marbles
• 4 black marbles
• 2 yellow marbles
A marble will be drawn from the bag and replaced 100 times. What is a reasonable prediction
for the number of times a green or black marble will be drawn?

To predict the number of times a green or black marble will be drawn, we need to consider the proportion of green and black marbles compared to the total number of marbles in the bag.

First, let's calculate the total number of marbles in the bag:
Total number of marbles = 5 red + 6 blue + 3 green + 4 black + 2 yellow = 20 marbles

Next, let's calculate the proportion of green and black marbles:
Proportion of green marbles = 3 green / 20 total = 0.15 or 15%
Proportion of black marbles = 4 black / 20 total = 0.20 or 20%

Now, since we are replacing the marbles after each draw, the probability of drawing a green or black marble will remain constant. Thus, the reasonable prediction for the number of times a green or black marble will be drawn in 100 draws is equal to the product of the probability and the number of draws:

Number of times a green or black marble will be drawn = Probability of drawing green or black marble * Number of draws

Applying this to our situation:
Number of times a green or black marble will be drawn = (0.15 + 0.20) * 100
= 0.35 * 100
= 35

Therefore, the reasonable prediction is that a green or black marble will be drawn approximately 35 times.