What is the molality of 750 g of water with 48 g of CuSO4 dissolved within it?
So the formula is moles/ Kg of solvent so how would this fit?
Number of moles = Given mass/Molecular Mass
Molecular Mass of CuSO4 = 159.6 g
Give mass = 48g
=> Number of moles = 48/159.6 = 3/10 = 0.3
=> Molality = Number of moles/Kg of solvent
= 0.30/0.75
= 10/25
= 0.4 m