A camel can carry a maximum weight equal to either 18 identical large jugs of water of 30 identical small jugs of water if the camel is loaded with 25 small jugs of water how many additional large jugs of water can the camel carry

Question

A camel can carry a maximum weight equal to either 18 identical large jugs of water of 30 identical small jugs of water if the camel is loaded with 25 small jugs of water how many additional large jugs of water can the camel carry

Answer 1

18 L = 30 S ... 3 L = 5 S

30 - 25 = 5 ... 5 S = 3 L

Answer 2

If a camel can carry a maximum weight equal to 18 identical large jugs of water or 30 identical small jugs of water, and it is already loaded with 25 small jugs of water, we can calculate how many additional large jugs of water it can carry.

To find the weight of 25 small jugs of water, we can assume the weight of each small jug is the same, let's say x.
So the weight of 25 small jugs is 25x.

Now, we need to find how many additional large jugs of water can be carried, considering that the camel can carry a maximum weight of 18 large jugs.

Let the weight of each large jug be y.

Since the camel can carry a maximum weight equal to 18 large jugs, the weight of those 18 large jugs is 18y.

To find how many additional large jugs can be carried, we subtract the weight of the small jugs from the maximum weight:

18y - 25x = additional weight that can be carried.

Please provide the weights of the large jugs (y) and the small jugs (x) so that I can help you calculate the additional weight that can be carried by the camel.

Answer 3

To find out how many additional large jugs of water the camel can carry, we need to determine the weight of 25 small jugs of water and then divide it by the weight of one large jug of water.

Let's assume the weight of one large jug of water is "L" and the weight of one small jug of water is "S". We know that the camel can carry either 18 large jugs or 30 small jugs.

So, we can set up the following equation:

18L = 30S

Next, let's find the weight of 25 small jugs of water:
25S

Now, to find the number of additional large jugs the camel can carry, we divide the weight of the small jugs by the weight of one large jug:
(25S) / L

To solve this equation, we need to determine the ratio between the weight of the large and small jugs. If we have this ratio, we can substitute it into the equation and calculate the number of additional large jugs the camel can carry.