Physics

A 8.9 kg bowling ball traveling at 16.7 m/s strikes a 1.1 kg bowling pin. The impact slows the bowling ball to 11.4 m/s.



Determine the velocity given to the pin.

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asked by Rm
  1. Some INFO is missing!

    Given:
    M1 = 8.9kg, V1 = 16.7 m/s.
    M2 = 1.1kg, V2 = 0.
    V3 = 11.4 m/s = Velocity of M1 after collision.
    V4 = ? = Velocity of M2 after collision.

    Momentum before = Momentum after:
    M1*V1 + M2*V2 = M1*V3 + M2*V4.
    8.9*16.7 + 1.1*0 = 8.9*11.4 + 1.1*V4,
    V4 = ?

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    posted by Henry

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