# Physics

A 8.9 kg bowling ball traveling at 16.7 m/s strikes a 1.1 kg bowling pin. The impact slows the bowling ball to 11.4 m/s.

Determine the velocity given to the pin.

1. 0
2. 0
3. 31
1. Some INFO is missing!

Given:
M1 = 8.9kg, V1 = 16.7 m/s.
M2 = 1.1kg, V2 = 0.
V3 = 11.4 m/s = Velocity of M1 after collision.
V4 = ? = Velocity of M2 after collision.

Momentum before = Momentum after:
M1*V1 + M2*V2 = M1*V3 + M2*V4.
8.9*16.7 + 1.1*0 = 8.9*11.4 + 1.1*V4,
V4 = ?

1. 0
2. 0
posted by Henry

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