A 7kg mass on a 12 N/m spring oscillates with an amplitude of 23cm.
What is the frequency of its oscillation in Hz?
Find the period - 2pi * sqrt(m/k) = 4.799
frequency = 1 / period = 0.208
Is that right?
f = (1/2pi)sqrt(k/m)
f = (1/6.28)sqrt(12/7)
f = .208
yes
To find the frequency of the oscillation, you can use the formula:
Frequency (f) = 1 / Period (T)
Where the period (T) is given by the equation:
T = 2π * sqrt(m/k)
In this case, the mass (m) is 7 kg and the spring constant (k) is 12 N/m. Plugging these values into the equation, we get:
T = 2π * sqrt(7/12) ≈ 4.799 seconds
Now, to calculate the frequency, we can use the formula:
f = 1 / T
Substituting the value of T into the equation, we get:
f = 1 / 4.799 ≈ 0.208 Hz
So, yes, you are correct. The frequency of the oscillation is approximately 0.208 Hz.