ann is 20 years older than her daughter faye. three years from now she will be six times as old as her daughter. find their present ages. This is my work: ( i'm not sure if it's correct ) Now 3 yrs from now Ann A A+3 Faye 6A 6A+3
A man has a daughter and son. The son is three times older than the daughter. In one year the man will be six times as old as the daughter is now. In ten years the man will be fourteen year older than the combined ages of his
the sum of the ages of Sylvana’s two daughters is 60. If the older daughter is three years older than the younger daughter, and the younger daughter’s age is y, write an equation that could be used to solve this problem.
A. John is now 10 years older than Marcus. Three times John's age 5 years from now will be the same as five times Marcus's age 5 years ago. How old is John now? B. In 1 year Kristen will be four times as old as Danielle. Ten years