A rotary speed of 2010 m/s. The rotating rod of 15.7 cm long. Assume the speed quoted is that of the end of the rod. What is the centripetal acceleration at the end of the rod?
To find the centripetal acceleration at the end of the rod, we can use the formula:
Centripetal acceleration (a) = (rotary speed (v))^2 / radius (r)
First, let's convert the length of the rod from centimeters (cm) to meters (m):
Length of the rod (r) = 15.7 cm = 15.7/100 m = 0.157 m
Now we can find the centripetal acceleration by plugging in the given values:
a = (2010 m/s)^2 / 0.157 m
To calculate this, you square the value of the rotary speed and then divide it by the radius.
a = 4040100 m^2/s^2 / 0.157 m
Now divide 4040100 m^2/s^2 by 0.157 m to get the centripetal acceleration.
a ≈ 25,739,491.08 m/s^2
So, the centripetal acceleration at the end of the rod is approximately 25,739,491.08 m/s^2.