physics

On planet Seeturn, the free fall acceleration is 9.800 N/kg but there is also a strong downward electric field that is uniform close to the planet's surface. A 2.00 kg ball having a charge of 5.00 micro C (5.00*10-6) is thrown upward at a speed of 20.1 m/s, and it hits the ground after an interval of 4.10s. What is the potential difference between the starting point and the top point of the trajectory?

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asked by david
  1. E is uniform? then force is Eq, and is downward.

    force gravity=9.8
    force electric=5e-6*E
    total acceleration down=totalforce/mass

    at the top, vfinal=zero
    vf=vi+at where t=2.05sec
    you know vi, t, solve for a. With that a, set it equal to totalforce/mass
    and solve for E. Voltage=E*height achieved.
    vf^2=vi^2+2ad, now solve for d, knowing E just found.
    voltage difference is E*d

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    posted by bobpursley
  2. What is the final answer going to be and where did you get that t is 2.05 seconds

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    posted by david

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