A person's density 980 kg/m3 is floating in salt-saturated water if density 1210 kg/m3.
1. what percentage of the person's volume is submerged?
2. what percentage of the person's volume is above the surface?
I found the percent submerged by doing Vsub/Vob, and got that the object is 80.99% submerged. I can't figure out how much is above the surface?
what is 100-80.99 ?
To find the percentage of the person's volume that is above the surface, we can calculate the percentage of the person's volume that is submerged and subtract it from 100%. Let's break down the steps to find the solution:
1. Determine the percentage of the person's volume that is submerged:
To find this, you correctly calculated Vsub / Vob, where Vsub represents the submerged volume and Vob represents the total or object's volume. You mentioned that the person's volume is 80.99% submerged.
2. Find the percentage of the person's volume that is above the surface:
Now, subtract the percentage of the submerged volume from 100% to get the percentage above the surface:
100% - 80.99% = 19.01%
Therefore, approximately 19.01% of the person's volume is above the surface.
By following the steps above, you can determine the percentage of the person's volume that is submerged and the percentage above the surface.