Math

after a cyclist has gone 2/3 of her route, she gets a puncture in a tire. Finishing on foot, she spends twice as long walking as she did riding. How many times as fast does she ride as walk?

I know that the answer is 4 but do not know how to get to this answer. Can you please show me the steps?

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  1. it takes her twice as long to go half as far

    so she walks a quarter as fast as she rides

    w = (d/2) / 2t = 1/4 d/t

    r = d/t

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