Log20+3log2-lpgq.6
I suspect a typo, but just using the properties of logs, that would be
log20 + log(2^3) - log(q.6)
= log20 + log8 - log q.6
= log(160/q.6)
fix your typo and proceed
log20 + log(2^3) - log(q.6)
= log20 + log8 - log q.6
= log(160/q.6)
fix your typo and proceed