Calculate the mass CaCl2 · 6 H2O needed to
prepare of 0.123 m CaCl2(aq), by using 373 g
of water.
Answer in units of g.
molality=moles/kgwater
molality=mass/(kgwater*molmass)
mass=molality*molmass*kgwater
= .123*219.0757*.373
To calculate the mass of CaCl2 · 6 H2O needed to prepare a 0.123 m CaCl2(aq) solution using 373 g of water, we need to follow a few steps:
Step 1: Determine the molarity (m) of the CaCl2(aq) solution.
We are given that the molarity of the solution is 0.123 m CaCl2(aq).
Step 2: Calculate the number of moles of CaCl2 required using the molarity and volume of the solution.
The volume of the solution is not given, so we need additional information to proceed with this step. Please provide the volume of the solution in liters.
Once we have the volume of the solution, we can use the formula:
moles = molarity * volume
Step 3: Calculate the molecular weight of CaCl2 · 6 H2O.
The formula weight, or molecular weight, of CaCl2 · 6 H2O is the sum of the atomic weights of each element present in the compound. You can find the atomic weights from a periodic table.
Step 4: Calculate the mass of CaCl2 · 6 H2O using the number of moles and the molecular weight.
The mass can be calculated using the formula:
mass = moles * molecular weight
With the volume of the solution, we can proceed with the calculations. Please provide the volume of the solution so we can complete the answer.