Physics 1

A 1400 kg car traveling at a speed of 34 m/s skids to a halt on wet concrete where μk = 0.50. How long are the skid marks?

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asked by Logan
  1. vf^2=vo^2-1/2 *.4*1400*9.8*d
    solve for d, given vf=0

  2. weight = m g = 1400 * 9.81
    friction force = .5 * 1400 * 9.81 = 6867 N

    a = F/m = 6867/1400 = -4.9 (half a g of course)

    v = 34 - 4.9 t
    v = 0 at stop
    so
    t = 6.94 seconds
    d = 34 t - (1/2)(4.9) t^2
    = 34(6.94) - 2.45*6.94^2
    = 236 - 118
    = 118 meters

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    posted by Damon
  3. Thanks so much!!

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    posted by Logan

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