Chemistry

Hey bob- Here's what I got so far:

3AgNO3 + Na3PO4 ---> Ag3PO4 + 3NaNO3

Silver nitrate and sodium phosphate are reacted in equal amounts of 200. g each. How many grams of silver phosphate are produced?

1. What is the limiting?
2. How much silver phosphate is produced?
3. How much is in excess?

200gAGNO3/170= 1.18 AGNO3
200gNA3PO4/164= 1.22 Ag3PO4

Not sure of the next step....here's what I got:

419 AG3PO4 x 3 = 1257 AG3PO4

Is AG3PO4 the limiting reagent??

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩
  1. 200gAGNO3/170= 1.18 AGNO3
    200gNA3PO4/164= 1.22 Ag3PO4
    3AgNO3 + Na3PO4 ---> Ag3PO4 + 3NaNO3
    One needs three time the silver nitrate, you dont have near that, so silver nitrate is the limiting reageant. So you will consume all you have 1.18 moles, and you will get 1.18/3 moles of silver phosphate.
    On the sodium phosphate, you will consume 1.18/3 moles of it, you had 1.22 to start, so the left over is the difference, and you cna convert that to grams

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
    👤
    bobpursley
  2. Can you check my answer from your last tips:

    1. Ok I think I understand. Still a little unsure tho where we're getting the 3 times the silver nitrate from for silver nitrate to be limiting reagent.

    2. 1.18/3=.39 x 419 Ag3PO4 = 163g Ag3PO4 produced??

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  3. 3. 200g Na3PO4 - 163 = 36g Ag3PO4??

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  4. The three times is because your balanced equation says you need three silver nitrate molecules for every sodium phosphate molecule.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  5. You do not have that much silver nitrate so it limits the reaction.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  6. Gotcha, thanks. Can you one of you guys see if I got 2 & 3 correct from the tips bob was giving me.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  7. so you use 1.18 mols of silver nitrate
    that needs 1.18/3 = .393 mols of sodium phosphate. For every mol of sodium phosphate you get a mol of silver phosphate so you get ,393 mols of Silver Phosphate
    you have 1.22 mols of sodium phosphate
    so you will have 1.22 - .39 = .83 mols of sodium phosphate left over.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  8. I will leave you to convert mols to grams :)

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  9. I only do mols.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  10. 3.) Cool that makes sense. So I believe this is how you convert mole to gram:

    .83 x 164g/mol = 136g Na3PO4 left over

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  11. I assume your 164 g/mol is correct. I know O is 16 and Na is 23 but do not remember P . Not about to Google.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  12. Phosphorus is 31g.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  13. Ya and that equals 164. Thank you a ton for the help I've stomped on this whole problem for like a half an hour and I got lots more to do. This was my 2nd limiting reagent problem I've ever done so I'm still learning how to handle these.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  14. Would you have another 5 minutes to help me one more problem I'm stumped on???

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  15. I'll post it as a new problem. Its a Stoichemetric Problem that I'm completely stumped on. I think I have part of correct which i'd be happy to see if its correct so far or not.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩

Respond to this Question

First Name

Your Response

Similar Questions

  1. chemistry

    2Na3PO4 + 3CaCl2 ----> Ca3 (PO4)2 + 6NaCl how many moles of CaCl2 remain if .10 mol Na3PO4 and .40 mol CaCl2 are used? When amounts of both materials are listed one must worry about which is the limiting reagentalthough the

  2. chem

    One method for reclaiming silver metal from silver chloride results in a 94.6% yield. Calculate the actual mass of silver that can be produced in this reaction if 100.0 g of silver chloride is converted to silver metal. 2AgCl(s) y

  3. Chemistry(Please check answer)

    The Ksp values for three salts are given: AgCl = 1.0e-10 Ag2CO3 = 6.3e-10 Ag3PO4 = 2.0e-21 Determine the order of solubility for these three salts. My answer is AgCl > Ag2CO3 > Ag3PO4. Would you agree? Thank you.

  4. Chemistry

    A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4 will be needed to produce 400mL of a solution that has a concentration of Na+ ions of 1.10M ?

  1. Chemistry

    3AgNO3 + Na3PO4 ---> Ag3PO4 + 3NaNO3 Silver nitrate and sodium phosphate are reacted in equal amounts of 200. g each. How many grams of silver phosphate are produced? 1. What is the limiting? 2. How much silver phosphate is

  2. Chemistry

    Write ionic equation for the following: A. Na3PO4 + 3 AgNO3 --> 3 NaNO3 + Ag3PO4 B. (NH4)2SO4 + Ba(C2H3O2 + BaSO4

  3. Chemistry

    A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4 will be needed to produce 750 mL of a solution that has a concentration of Na^+ ions of 1.3 M?

  4. Physics

    Bob has just finished climbing a sheer cliff above a beach, and wants to figure out how high he climbed. All he has to use, however, is a baseball, a stopwatch, and a friend on the ground below with a long measuring tape. Bob is a

  1. Physics

    The pendulum bobs in the figure are made of soft clay so that they stick together after impact. The mass of bob B is 14 times that of bob A. Bob B is initially at rest. If bob A is released from a height h above its lowest point,

  2. Science- chemistry

    fuzzy silver coating is impure silver. it can be converted back into silver nitrate by reacting it with nitric acid what has been done to the reaction mixture to recover solid silver nitrate?

  3. chem

    what is [Ag^+] in a solution formed by mixing 25.0 ml of 0.10 M AgNO3 with 50.0 ml of 1.50 M Na3PO4. Ksp for Ag3PO4=1.0x10^-21

  4. chemistry

    A scientist wants to make a solution of tribasic sodium phosphate,Na3PO4 , for a laboratory experiment. How many grams of Na3PO4 will be needed to produce 550 ml of a solution that has a concentration of Na+ ions of 1.40M ?

View more similar questions or ask a new question.