# math

I'm a little confused on how to solve this system of equations.

5a=5
6b-3c=15
2a+7c=-5

Thanks

1. The first equation gives a = 1 when you divide both sides by 5

Now do the third equation substituting 1 for a
2*1 + 7 c = -5
7 c = -7
c = -1

so now we have a = 1 and c = -1
Use those in the middle equation
6 b - 3 (-1) = 15
6 b + 3 = 15
6 b = 12
b = 2

posted by Damon
2. Ah, I get it now. Thanks

posted by Anonymous

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