Calcium carbide (CaC2) reacts with water to produce acetylene as follows. The complete reaction of 25.2g CaC2 produces ____ grams of calcium hydroxide.
CaC2(s) + 2H¬2O(g) → Ca(OH¬)2(s) + C2H2
for each mole of calcum carbide, you get one mole of calcium hydroxide.
how many moles of CaC2 do you have?
25/69.0
how many grams of Ca(OH)2?
the above moles x 74.1
To determine the grams of calcium hydroxide (Ca(OH)2) produced from the reaction of 25.2g of calcium carbide (CaC2), we need to follow these steps:
Step 1: Convert the mass of CaC2 to moles.
Given: Mass of CaC2 = 25.2g
Molar mass of CaC2 = 64.1 g/mol
Number of moles of CaC2 = Mass / Molar mass
Number of moles of CaC2 = 25.2g / 64.1 g/mol
Step 2: Use the balanced equation to determine the mole ratio between CaC2 and Ca(OH)2.
From the balanced equation, we can see that 1 mole of CaC2 reacts to produce 1 mole of Ca(OH)2.
Therefore, the mole ratio between CaC2 and Ca(OH)2 is 1:1.
Step 3: Convert the number of moles of CaC2 to moles of Ca(OH)2.
Since the mole ratio between CaC2 and Ca(OH)2 is 1:1, the number of moles of Ca(OH)2 will be the same as the number of moles of CaC2.
Step 4: Convert the moles of Ca(OH)2 to grams.
Molar mass of Ca(OH)2 = 74.1 g/mol
Mass of Ca(OH)2 = Number of moles of Ca(OH)2 × Molar mass of Ca(OH)2
Putting it all together:
Number of moles of CaC2 = 25.2g / 64.1 g/mol
Number of moles of Ca(OH)2 = Number of moles of CaC2
Mass of Ca(OH)2 = Number of moles of CaC2 × Molar mass of Ca(OH)2
Calculate the final answer using these steps.
To find the number of grams of calcium hydroxide produced, we need to calculate the molar mass of calcium hydroxide (Ca(OH)2) and use it to convert the given mass of calcium carbide (CaC2) to moles. Then, we can use the balanced equation to determine the ratio between calcium carbide and calcium hydroxide to find the number of moles of calcium hydroxide produced. Finally, we can convert the moles of calcium hydroxide to grams using its molar mass.
1. Calculating the molar mass of calcium hydroxide (Ca(OH)2):
- Atomic mass of calcium (Ca) = 40.08 g/mol
- Atomic mass of oxygen (O) = 16.00 g/mol
- Atomic mass of hydrogen (H) = 1.01 g/mol
- Molar mass of Ca(OH)2 = (40.08 g/mol) + 2(16.00 g/mol) + 2(1.01 g/mol) = 74.09 g/mol
2. Converting the mass of calcium carbide to moles:
- Given mass of calcium carbide = 25.2 g
- Molar mass of CaC2 = (40.08 g/mol) + 2(12.01 g/mol) = 64.10 g/mol
- Moles of CaC2 = (25.2 g) / (64.10 g/mol)
3. Using the balanced equation, the ratio between CaC2 and Ca(OH)2 is 1:1.
So, the moles of Ca(OH)2 produced will be the same as the moles of CaC2.
4. Converting the moles of Ca(OH)2 to grams:
- Moles of Ca(OH)2 = Moles of CaC2
- Mass of Ca(OH)2 = Moles of Ca(OH)2 × Molar mass of Ca(OH)2
Now, let's calculate the final answer:
Moles of CaC2 = (25.2 g) / (64.10 g/mol)
Mass of Ca(OH)2 = Moles of Ca(OH)2 × Molar mass of Ca(OH)2
The result will give you the grams of calcium hydroxide produced.