20.6 gm NaBr solved in 500 ml of water. What will be the molarity of solvent. Where Na 23 n Br 80
mols NaBr = grams/molar mass = ?
Then M = mols/L
To find the molarity of the solvent, we need to determine the number of moles of NaBr dissolved in the water and then divide it by the volume of the solvent (in liters). Here's how you can calculate it step by step:
Step 1: Calculate the number of moles of NaBr:
Since we are given the mass of NaBr (20.6 gm) and the molar masses of Na (23 g/mol) and Br (80 g/mol), we can use the formula:
Number of moles = Mass / Molar mass
Number of moles of NaBr = 20.6 gm / (23 g/mol + 80 g/mol)
Number of moles of NaBr = 20.6 gm / 103 g/mol
Number of moles of NaBr ≈ 0.2 mol
Step 2: Convert the volume of the solvent to liters:
We are given the volume of water as 500 ml, which we need to convert to liters. Since 1 liter = 1000 ml, we have:
Volume of water = 500 ml / 1000 ml/L
Volume of water = 0.5 L
Step 3: Calculate the molarity of the solvent (water):
Now we can use the formula:
Molarity (M) = Number of moles / Volume (in liters)
Molarity (M) = 0.2 mol / 0.5 L
Molarity (M) = 0.4 M
Therefore, the molarity of the solvent (water) is 0.4 M.