hi, one question i have is for the following problem:"Two families meet at a park for a picnic. At the end of the day, they part ways. Family A leaves 15 mins after family B and travels east at an average speed of 42mph; while, family b travels west at an average speed of 50 mph. Both families have approximately 160 miles to travel.
Find time (in hours and minutes that it takes for them to be 120 apart." For my equation i have it set up 42x-630+50=120. Is this correct. I set up a table with
r t d and for family a my equation for distance was 42(x-15) and my equation for Family B distance was 50x and then i combined the two to end up with 92x-630=120
15 minutes is 1/4 hour. So, adding up the distances after x hours, we have
50x + 42(x - 1/4) = 120
To solve the problem, you need to find the time it takes for Family A and Family B to be 120 miles apart. Let's go through the solution step by step.
First, let's set up the equations for the distances of each family:
Family A's distance = 42 * (x - 15) [since Family A leaves 15 minutes later]
Family B's distance = 50 * x
Now, let's set up the equation for the difference in distances:
Family A's distance - Family B's distance = 120
42 * (x - 15) - 50 * x = 120
To solve this equation, you can simplify it:
42x - 630 - 50x = 120
-8x - 630 = 120
-8x = 120 + 630
-8x = 750
Now, let's solve for x by dividing both sides by -8:
x = 750 / -8
x = -93.75
It seems that you have made an error while setting up the equation. You can check the equation again and make sure it is correct. Let me know if you need further assistance!