physics

A box weighing 87 lb is being pulled with a rope that exerts a force of 60. lb at an angle of 15 degrees with the horizontal. if the coefficient of kinetic friction is .35, what is the kinetic friction?

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  1. force vertical =60*sin15 upwards
    friction=.35(87-60*sin15) lbs

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    bobpursley
  2. Fn = 87-60*sin15 = Normal force.

    Fk = u*Fn = 0.35 * Fn. = Force of kinetic friction.

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