Find the number of molecules of sodium bicarbonate present in 5.08 gram
mols Na2CO3 = grams/molar mass = ?
1 mol will contain 6.022E23 molecules.
what is the ph of 50ml buffer solution which is 2M in CH3COOH and 2M in CH3CooNa?
1 Initial PH before the addition of acids and base?
2 What is the new PH after 2ml of 6.00M HCl is added to this buffer?
3 what is the new PH after 2.00ml of 6.00M NaoH is added to the original buffer?
To find the number of molecules of sodium bicarbonate present in 5.08 grams, we need to use the concept of Avogadro's number and the molar mass of sodium bicarbonate.
Avogadro's number states that 1 mole of any substance contains 6.022 x 10^23 molecules.
First, we need to determine the molar mass of sodium bicarbonate (NaHCO3). The molar mass is calculated by adding up the atomic masses of each element in the compound.
- The atomic mass of sodium (Na) is 22.99 grams/mole.
- The atomic mass of hydrogen (H) is 1.01 grams/mole.
- The atomic mass of carbon (C) is 12.01 grams/mole.
- The atomic mass of oxygen (O) is 16.00 grams/mole.
Adding these values together, the molar mass of sodium bicarbonate is:
(1 x 22.99 g/mol) + (1 x 1.01 g/mol) + (1 x 12.01 g/mol) + (3 x 16.00 g/mol) = 84.01 g/mol
Now we can calculate the number of moles of sodium bicarbonate using the formula:
moles = mass (grams) / molar mass (grams/mole)
moles = 5.08 g / 84.01 g/mol
moles ≈ 0.0605 mol
Finally, we can use Avogadro's number to calculate the number of molecules:
number of molecules = moles x Avogadro's number
number of molecules ≈ 0.0605 mol x 6.022 x 10^23 molecules/mol
number of molecules ≈ 3.646 x 10^22 molecules
Therefore, there are approximately 3.646 x 10^22 molecules of sodium bicarbonate present in 5.08 grams.