A body is dropped the roof of a building 10 mtr high calculate the time and speed g =10 m/s

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  1. Distance from the ground = s = 10m
    Acceleration = g = a = 10m/s^2
    Initial speed = u = 0m/s (As it is dropped)

    Using the equation, s = ut + (1/2)at^2,
    => s = (1/2)at^2
    => t^2 = 2
    => t = root 2

    Use v = u + at for speed

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