Um how
do i balance these word equations for chemistry...
I think I'm suppose to look them up on a common table of ions and then I don't know wat to do
ferric Oxid --> iron oxygen
what exactly am i suppose to do
please tel me thr throught process that's suppose to go through my head while doing this.
If that's
ferric oxide ==> iron + oxygen, then the first step is to changer the words to chemical formula.
Fe2O3 ==> Fe + O2
The next step is to balance the equation which you do by changing the coefficients. (You may change only the coefficients--you may NOT change the subscripts).
2Fe2O3 ==> 4Fe + 3O2
Balancing word equations in chemistry involves ensuring that the number of atoms on both sides of the equation is equal. To balance the equation "ferric Oxid --> iron oxygen," you can follow these steps:
1. Start by writing down the names of the elements involved in the equation. In this case, we have "ferric" (which refers to iron with a +3 charge) and "Oxid" (which refers to oxygen).
2. Identify the chemical formulas for the elements. In this case, the chemical formula for ferric is Fe3+ (indicating a positive 3 charge) and oxygen is O2- (indicating a negative 2 charge).
3. Write the chemical formula for the reactants and products. The initial equation "ferric Oxid --> iron oxygen" can be represented as Fe3+ O2- --> Fe [?] O2 [?].
4. To balance the equation, start with the element that appears in the fewest places. In this case, it is the iron (Fe). Since there is one iron on the left side, we need to balance it by placing a coefficient in front of the product that contains iron (Fe). Let's assume we put a 2 in front, making the equation 2Fe3+ O2- --> Fe2 [?] O2 [?].
5. Now, let's work on balancing the oxygen (O). On the left side, there are two oxygen atoms, and on the right side, there are four oxygen atoms (O2 [?]). To balance it, we need to put a coefficient of 2 in front of the oxygen molecule on the left side, making the equation 2Fe3+ O2- --> Fe2 [?] O4 [?].
6. The equation still needs to be balanced as the charges do not match on both sides. The total charge on the left side is 6+ (2 * 3) - (2 * 2) = 10+. Therefore, the total charge on the right side should also be 10+. To achieve this, we need to balance the charges by placing a 5+ charge on the iron on the right side. This gives us the final balanced equation: 2Fe3+ O2- --> Fe2+ O4-.
Remember to always double-check your work to ensure that the equation is balanced correctly.
By using this step-by-step process, you can approach and balance various word equations in chemistry.