For a normal distribution with mean of 80 and a standard deviation of 8, find the number of standard deviations the raw score 67 is from the mean (Give answer as a positive value rounded to nearest hundredth).
(80 - 67) / 8
(67 - 80) / 8 = 13/8
To find the number of standard deviations a raw score is from the mean, you can use the formula:
\(z = \frac{x - \mu}{\sigma}\)
where:
- \(z\) is the number of standard deviations
- \(x\) is the raw score
- \(\mu\) is the mean
- \(\sigma\) is the standard deviation
In this case, the raw score is 67, the mean is 80, and the standard deviation is 8.
\(z = \frac{67 - 80}{8}\)
\(z = \frac{-13}{8}\)
\(z = -1.625\)
Since we need to give the answer as a positive value, we can take the absolute value of \(z\), which gives:
\(z = 1.625\)
Rounding this to the nearest hundredth, we get:
\(z \approx 1.63\)
Therefore, the raw score 67 is approximately 1.63 standard deviations below the mean of 80.