A 6.0 kg mass is pulled horizontally along a level surface where the coefficient of friction is
0.20. The mass accelerates at 0.68 m/s2.
a) What is the friction force acting on the mass?
b) What applied force is being used to pull the mass?
M*g = 6 * 9.8 = 58.8 N. = Wt. of Mass. = Normal force(Fn).
a. Fk = u*Fn = 0.20 * 58.8 = 11.8 N. - Force of kinetic friction.
b. Fap-Fk = M*a.
Fap = ?.
To find the friction force acting on the mass, we can use the equation:
friction force = coefficient of friction * normal force
where the normal force is the force exerted by the surface perpendicular to the mass. Since the mass is on a level surface, the normal force is equal to the weight of the mass.
a) Determine the friction force:
First, calculate the weight of the mass:
weight = mass * gravitational acceleration
= 6.0 kg * 9.8 m/s^2
= 58.8 N
Next, calculate the friction force:
friction force = coefficient of friction * normal force
= 0.20 * 58.8 N
= 11.76 N
Therefore, the friction force acting on the mass is 11.76 N.
b) Determine the applied force:
The applied force is the force used to pull the mass horizontally. It can be calculated using Newton's second law:
applied force = mass * acceleration
= 6.0 kg * 0.68 m/s^2
= 4.08 N
Therefore, the applied force used to pull the mass is 4.08 N.
To find the friction force acting on the mass, we can use the equation:
friction force (Ff) = coefficient of friction (μ) * normal force (N)
The normal force is the force exerted by the surface on the object perpendicular to the surface. For an object on a level surface, the normal force is equal to the weight of the object (mg), where m is the mass of the object and g is the acceleration due to gravity (approximately 9.8 m/s^2).
a) To calculate the friction force, we need to determine the normal force first:
normal force (N) = mg
Given that the mass (m) is 6.0 kg, and the acceleration due to gravity (g) is 9.8 m/s^2, the normal force is:
N = 6.0 kg * 9.8 m/s^2 = 58.8 N
Now we can calculate the friction force:
friction force (Ff) = 0.20 * 58.8 N
b) The applied force (Fa) can be calculated using Newton's second law:
Fa = m * a
Given that the mass (m) is 6.0 kg and the acceleration (a) is 0.68 m/s^2, the applied force is:
Fa = 6.0 kg * 0.68 m/s^2 = 4.08 N
So, the answers to the given questions are:
a) The friction force acting on the mass is 0.20 * 58.8 N = 11.76 N.
b) The applied force being used to pull the mass is 4.08 N.