This is what I have
x=1st interger
17-x= 2nd interger
equation:
x(x-17)=66
x^2-17x-66
then I have to factor it but I don't know the factors that is what I need help with finding that
I'm sorry, but I don't know how to figure it your way. However, since I gave you the answer in the last post, I hope you can figure out the correct way to show it in an equation.
it factors to (x-6)(x-11) = 0
so x = 6 or x=11
To factor the quadratic equation x^2 - 17x - 66, we need to find two numbers that multiply to -66 and add up to -17.
To do this, you can start by listing all the factor pairs of -66. These are:
1, -66
2, -33
3, -22
6, -11
Next, look for a pair of numbers that add up to -17. From the list above, we find that the pair -11 and 6 satisfies this condition.
So, we can rewrite the equation x^2 - 17x - 66 as:
(x - 11)(x + 6) = 0
By applying the zero product property, we know that either (x - 11) = 0 or (x + 6) = 0.
Now, you can solve for x in each equation.
Case 1: (x - 11) = 0
Solving for x, we add 11 to both sides of the equation:
x = 11
Case 2: (x + 6) = 0
Solving for x, we subtract 6 from both sides of the equation:
x = -6
Therefore, the two possible values for x are 11 and -6.