# maths

Solve for all x such that:
(1+(1/x))^(x+1)=(2000/1999)^1999

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1. I find only one root at about
x=2.7176022...
a reasonable approximation to e.

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2. Hmmm. That's not what I get.

(1+(1/2.7176022)) = 1.36797
1.36797^3.7176022 = 2.20537

(2000/1999)^1999 = 2.7176022

close, but not nearly correct.

(1+1/e)^(e+1) = 3.20527

I get a solution at x = -2000

(1+(1/-2000))^(-2000+1) = 2.7176022

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posted by Steve
3. Very true, x=-2000 solves the problem exactly.

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