What is the equation of the line, in slope-intercept form, that goes through the point (2,-3) with m=6 ?
Slope intercept form of a line that passes through point (x0,y0) with slope m is given by:
y=m(x-x0)+y0
Substitute values to get equation. Post your answer for checking if you wish.
well, I would start with:
y+3 = 6(x-2)
then arrange it to the form you want
You did not specify which of the intercept forms you want.
P(2,-3), m = 6.
Y = mx + b
-3 = 6*2 + b,
b = -15 = y-int.
Eq: Y = 6x - 15.
To find the equation of a line in slope-intercept form (y = mx + b), where m represents the slope and b represents the y-intercept, follow these steps:
Step 1: Identify the given values
The given point (2,-3) gives us the coordinates (x, y) = (2, -3), and the slope m = 6.
Step 2: Plug the values into the slope-intercept form equation
We need to substitute the values of the slope (m) and the coordinates (x,y) into the slope-intercept form equation:
y = mx + b
Using the given values:
-3 = 6(2) + b
Step 3: Solve for the y-intercept (b)
To solve for b, we can simplify the equation:
-3 = 12 + b
Subtract 12 from both sides:
b = -15
Step 4: Write the final equation
Using the value of b, we can now write the equation with the given slope and y-intercept:
y = 6x - 15
Therefore, the equation of the line that goes through the point (2,-3) with a slope of 6 is y = 6x - 15.