Each student in a class contributed as many paise as number of student in the class.teacher contributed rs 13 to make total collection of rs 49.how many students were in the class?
Let x be the number of students in the class.
(0.01x)(x) + 13 = 49
Answer is 6
49-13=36
root of 36 is 6
Let's assume that there were 'x' students in the class.
Each student contributed as many paise as the number of students in the class. So, each student contributed x paise.
The total collection from the students can be calculated by multiplying the contribution of each student (x paise) by the number of students (x).
Total collection from students = x * x = x^2 paise
The teacher also contributed Rs 13 to make the total collection Rs 49. Since 1 rupee is equal to 100 paise, the teacher contributed 13 * 100 = 1300 paise.
Total collection = Total collection from students + Contribution from teacher
49 * 100 = x^2 + 1300
Simplifying the equation:
4900 = x^2 + 1300
Rearranging the equation:
x^2 = 4900 - 1300
x^2 = 3600
Taking the square root on both sides of the equation:
x = √3600
x = 60
Therefore, there were 60 students in the class.
Let's assume the number of students in the class is "x".
Each student contributed as many paise as the number of students in the class. So, each student contributed x paise.
Now, we convert the total collection into rupees. Since 100 paise = 1 rupee, the total collection in rupees is 49/100 = 0.49 rupees.
The teacher also contributed 13 rupees. So, the total contribution of the students is 0.49 - 13 = -12.51 rupees.
But since we cannot have a negative contribution, there must be an error in the given information.
Please re-check the values provided, or ensure that the problem statement is correct.