3. A carbonate fusion was needed to free the Bi from a 0.6423-g sample of eulytite (2Bi2O3·3SiO2). The fused mass was dissolved in dilute acid, following which the Bi+3 was titrated with 27.36mL of 0.03369M NaH2PO4. The reaction is Bi+3 + H2PO4-  BiPO4(s) + 2H+. Calculate the percent purity of eulytite (1112g/mol) in the sample?

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The answer given to this question in most of the online answers is not correct, the correct answer is 𝟕𝟗.𝟖%

To calculate the percent purity of eulytite in the sample, we need to determine the amount of Bi+3 present in the sample and compare it to the theoretical amount of Bi+3 that would be present if the sample was 100% pure.

Let's break down the calculation into steps:

1. Calculate the moles of NaH2PO4 used in the titration:
Moles of NaH2PO4 = Concentration of NaH2PO4 x Volume of NaH2PO4 used
Moles of NaH2PO4 = 0.03369 M x (27.36 mL / 1000 mL)

2. Since the stoichiometric ratio between Bi+3 and NaH2PO4 is 1:1, the number of moles of Bi+3 is equal to the number of moles of NaH2PO4.
Moles of Bi+3 = Moles of NaH2PO4

3. Calculate the mass of Bi+3 in the sample:
Mass of Bi+3 = Moles of Bi+3 x Molar mass of Bi
Molar mass of Bi = 208.98 g/mol

4. Calculate the percent purity of eulytite:
Percent purity of eulytite = (Mass of Bi+3 / Mass of the sample) x 100%

Now, let's plug in the values and calculate the answer.

Given:
- Mass of the sample = 0.6423 g
- Molar mass of eulytite = 1112 g/mol

Step 1:
Moles of NaH2PO4 = 0.03369 M x (27.36 mL / 1000 mL) = 0.0009202704 mol

Step 2:
Moles of Bi+3 = Moles of NaH2PO4 = 0.0009202704 mol

Step 3:
Mass of Bi+3 = Moles of Bi+3 x Molar mass of Bi = 0.0009202704 mol x 208.98 g/mol = 0.19211 g

Step 4:
Percent purity of eulytite = (Mass of Bi+3 / Mass of the sample) x 100%
Percent purity of eulytite = (0.19211 g / 0.6423 g) x 100% = 29.91%

Therefore, the percent purity of eulytite in the sample is approximately 29.91%.

mols NaH2PO4 = M x L = ?

mols Bi^3+ = mols NaH2PO4 from the coefficients in the balanced titration equation (1:1).
Convert mols Bi^3+ to mols eulytite by mols Bi^3+ x (molar mass eulytite/2*atomic mass Bi) = ?
Then g eulytite = mols eulytite x molar mass eulytite.
Then % eulytite = (g/mass sample)*100 = ?