Given that
R
=
3
x
+
9
y
Find
x
when
y
=
6
and
R
=
7
Give your answer as an improper fraction in its simplest form
-47/3
-47/3
Can't say I care much for your text formatting. Since you seem to be dealing with fractions, I assume you meant to say
R = 3/x + 9/y
So, just plug in your numbers and solve for x:
7 = 3/x + 9/6
If I got the function wrong, just fix it and plug in the numbers to get ready to find x.
yo idk
yes
Given that
R
=
3
x
+
9
y
Find
x
when
y
=
6
and
R
=
7
Give your answer as an improper fraction in its simplest form.
= ?
To find the value of x when y = 6 and R = 7, we can substitute the given values into the equation R = 3x + 9y and solve for x.
First, substitute y = 6 and R = 7 into the equation:
7 = 3x + 9(6)
Next, simplify the equation by multiplying 9 by 6:
7 = 3x + 54
Then, subtract 54 from both sides of the equation to isolate 3x:
7 - 54 = 3x
Simplify:
-47 = 3x
Finally, divide both sides of the equation by 3 to solve for x:
-47/3 = x
So the value of x when y = 6 and R = 7 is -47/3.