Mathew rolls a number cube labeled with the numbers 1−6. He then flips a fair coin. What is the probability that he rolls a 4 and flips a head
Pr(4;h)=1/6 * 1/2 = 1/12
why not
To find the probability that Mathew rolls a 4 and flips a head, we need to multiply the probabilities of each event happening.
The probability of rolling a 4 on a number cube is 1/6, as there are 6 equally likely outcomes.
The probability of flipping a head on a fair coin is 1/2, as there are 2 equally likely outcomes.
To find the overall probability, we multiply these probabilities:
Probability of rolling a 4 and flipping a head = (1/6) * (1/2) = 1/12
Therefore, the probability that Mathew rolls a 4 and flips a head is 1/12.
To find the probability of Mathew rolling a 4 and flipping a head, we need to consider the individual probabilities of each event and then multiply them together.
First, let's determine the probability of rolling a 4 on the number cube. Since the cube is labeled with numbers 1-6, there are 6 possible outcomes, and only 1 of them is a 4. Therefore, the probability of rolling a 4 is 1/6.
Next, let's determine the probability of flipping a head. Since the coin is fair, it has two equally likely outcomes: heads or tails. Therefore, the probability of flipping a head is 1/2.
To find the probability of both events happening together, we multiply the individual probabilities. Therefore, the probability of rolling a 4 and flipping a head is (1/6) * (1/2) = 1/12.
So the probability that Mathew rolls a 4 and flips a head is 1/12.