what volume of carbondioxide is produced when 10g of Hcl reacts completely with caco3
caco3+2HCl=cacl2+H2o+Co2
moles ofHCl=10/36.5=0.27
volume:volume
2HCl:CO2
2:1
24000*2:24000
480000:24000
2700:x
x=1350cm3
.27 mols HCl agree
so
.135 mols CO2--- agree
at standard temp and pressure a mol is 22.4 liters
.135 mol*22.4 liters/mol= 3 liters
a liter is 1000 cm^3
so I get 3,000 cm^3
To calculate the volume of carbon dioxide (CO2) produced when 10g of HCl reacts completely with CaCO3, you will first need to find the number of moles of HCl.
The molecular weight of HCl is 36.5 grams/mole. To find the number of moles of HCl, divide the given mass (10g) by the molecular weight (36.5 g/mol):
0.27 moles = (10g HCl) / (36.5 g/mol)
Next, refer to the balanced chemical equation:
CaCO3 + 2HCl -> CaCl2 + H2O + CO2
From the equation, you can see that the ratio between 2HCl and CO2 is 2:1. This means that for every 2 moles of HCl, 1 mole of CO2 is produced.
Therefore, the 0.27 moles of HCl will produce half that amount, or 0.135 moles of CO2 (0.27 moles HCl * 1/2 = 0.135 moles CO2).
To calculate the volume of CO2, you will need to know the molar volume of any gas at standard temperature and pressure (STP), which is defined as 22.4 liters/mole.
Since the given molar volume is in cm3, convert liters to cm3 by multiplying by 1000:
22.4 L/mol * 1000 cm3/L = 22400 cm3/mol.
Next, set up a ratio of the molar volumes of CO2 to determine the volume of CO2 produced:
(22400 cm3/mol of CO2) : (0.135 moles of CO2) = x cm3 : 1 mole
Now, solve for x (the volume of CO2 in cm3):
x = (22400 cm3/mol of CO2) * (0.135 moles of CO2)
x = 3024 cm3
Therefore, the volume of carbon dioxide produced when 10g of HCl reacts completely with CaCO3 is 3024 cm3.