Suppose that in a given year, the probability that it will rain on September 21 is .358. What are the odds of it raining on September 21?
How would a solve this?
I would like to know the steps, not the answer.
Thanks!
odds are defined slightly different from probability.
odds in favour of some event
= prob(of that event) : prob (not that event)
so odds in favour of rain on Sept 21
= .358 : .642
= 358 : 642
reduce to lowest term ratio
To calculate the odds of an event occurring, you need to divide the probability of the event occurring by the probability of the event not occurring. In this case, the probability of it raining on September 21 is given as 0.358.
To find the probability of it not raining on September 21, you subtract the probability of it raining from 1. So, the probability of it not raining is 1 - 0.358 = 0.642.
Now, you can calculate the odds by dividing the probability of it raining (0.358) by the probability of it not raining (0.642): 0.358 / 0.642.
Simplifying this calculation will give you the odds.