Joe takes his wife and four children to the movies. their tickets cost $56. the adult tickets cost twice as much as the children's tickets. how much is one adult ticket?
children --- x
adults ------2x
Joe + wife + 4 children = 56
2x + 2x + 4x = 56
x = 7
state your conclusion.
To find the cost of one adult ticket, we can first set up an equation using the given information.
Let's say the cost of a child's ticket is x dollars.
The cost of an adult's ticket is twice the cost of a child's ticket, so it would be 2x dollars.
Now, according to the information given, Joe takes his wife and four children, which means there are five tickets in total. Since their total cost is $56, we can write the equation:
4x + 2x = $56
To solve this equation, we need to combine like terms:
6x = $56
Next, let's isolate x by dividing both sides of the equation by 6:
x = $56/6
Now, let's simplify the right side of the equation:
x = $9.33 (rounded to two decimal places)
So, the cost of one child's ticket is $9.33.
Since the cost of an adult ticket is twice the cost of a child's ticket, the cost of one adult ticket would be:
2 * $9.33 = $18.66
Therefore, one adult ticket costs $18.66.