What is the energy of a photon of yellow light with a frequency of 5.14 × 1014 Hz?
photon energy = h * frequency
h = 6.626*10^-34 Joule seconds * 5.14*10^14 cycles/second
To calculate the energy of a photon, we can use the equation:
E = hf
where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J·s), and f is the frequency of the light wave.
In this case, we are given a frequency of 5.14 x 10^14 Hz. To find the energy of the yellow light photon, we can substitute the values into the equation:
E = (6.626 x 10^-34 J·s) x (5.14 x 10^14 Hz)
First, let's calculate the product of the two numbers in parentheses:
(6.626 x 5.14) x (10^-34 x 10^14) = 34.02988 x 10^-20 J·s
Next, simplify the second part of the equation:
10^-20 J·s = 10^(-20+34) J = 10^14 J
Now, we can multiply the two parts together:
E = 34.02988 J x 10^14 J
Finally, we can express the answer using proper scientific notation:
E = 3.402988 x 10^-5 J
Therefore, the energy of a photon of yellow light with a frequency of 5.14 x 10^14 Hz is 3.402988 x 10^-5 Joules.