Question

FIND N:

(6^(3n)*9^(n+1))/8^n=1

Answer 1

6^(3n) = 2^(3n) * 3^(3n) = 8^n * 27^n

9^(n+1) = 3^(2n+2)

so you have

8^n * 3^(5n+2) = 8^n
3^(5n+2) = 1 = 3^0
5n+2 = 0
n = -2/5