If ab = 8 and a^2+b^2=16, then what is the value of (a+b)^2?
we all know u came from RSM
ab = 8, a^2 + b^2 = 16.
(a + b)^2 = a^2 + 2ab + b^2 =
(a^2 + b^2) + 2ab.
16 + 2*8 = 32.
pov: your doing rsm
pov your doing rsm on sunday night before class with your dad and only after solving the bonus problems you have a 97, uh totally not me
when you're failing RSM
lol
This answer thread has become an RSM chat app
To find the value of (a+b)^2, we can use the identities (a+b)^2 = a^2 + 2ab + b^2. We know that ab = 8, and a^2 + b^2 = 16.
Substituting the given values into the identity, we have:
(a+b)^2 = a^2 + 2ab + b^2
= 16 + 2(8)
= 16 + 16
= 32
Therefore, the value of (a+b)^2 is 32.
me still doing this problem bc im in rsm *insert skull emoji*
We know that (a+b)^2
= a^2 + 2ab + b^2
= ...