Algebra

Determine the discriminant for the quadratic equation -3 = x^2 + 4x + 1. Based on the discriminant value, how many real number solution does the equation have?

Discriminant =b^2 - 4ac

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  1. -3 = x^2 + 4x + 1
    x^2 + 4x + 4 = 0 , so a=1, b=4, and c=4

    just plug it in.

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  2. A.1 bcuz d=0 =is 1

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