s²-6s+8=0
first you see what multiplies into 8, and + or - = -6
1 x 8
2 x 4
(s-4)(s-2)
thank you
To solve the quadratic equation s^2 - 6s + 8 = 0, we can use the quadratic formula. The quadratic formula states that for any quadratic equation in the form of ax^2 + bx + c = 0, the solutions can be found using the formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this case, our equation is s^2 - 6s + 8 = 0, so a = 1, b = -6, and c = 8. Substituting these values into the quadratic formula, we have:
s = (-(-6) ± √((-6)^2 - 4(1)(8))) / (2(1))
s = (6 ± √(36 - 32)) / 2
s = (6 ± √4) / 2
s = (6 ± 2) / 2
Now we have two possible solutions:
s = (6 + 2) / 2 = 8 / 2 = 4
s = (6 - 2) / 2 = 4 / 2 = 2
Therefore, the solutions to the equation s^2 - 6s + 8 = 0 are s = 4 and s = 2.