What mass of solute is needed to make the following solutions:
0.238 M FeCl3 solution in 1000. mL of solution.
mass=.238*1*molmassFeCl3
To find the mass of solute needed to make a 0.238 M FeCl3 solution in 1000 mL of solution, you will need to use the formula:
Molarity (M) = (moles of solute) / (volume of solution in liters)
First, convert the given volume of solution from milliliters to liters:
1000 mL ÷ 1000 = 1 L
Next, rearrange the formula to solve for moles of solute:
(moles of solute) = Molarity (M) × volume of solution (in liters)
Substitute the given values into the equation:
(moles of solute) = 0.238 M × 1 L
Now, we need to determine the molar mass of FeCl3, which consists of iron (Fe) and three chlorine (Cl) atoms. The molar mass can be calculated by multiplying the atomic masses of the elements and summing them up.
The atomic mass of iron (Fe) is approximately 55.85 g/mol, and the atomic mass of chlorine (Cl) is approximately 35.45 g/mol. Since there are three chlorine atoms in FeCl3, the total molar mass is:
molar mass of FeCl3 = (1 × atomic mass of iron) + (3 × atomic mass of chlorine)
molar mass of FeCl3 = (1 × 55.85 g/mol) + (3 × 35.45 g/mol)
Calculate the molar mass:
molar mass of FeCl3 = 55.85 g/mol + 106.35 g/mol
molar mass of FeCl3 ≈ 162.20 g/mol
Now, calculate the mass of FeCl3 needed to make the solution. To do this, multiply the moles of solute by the molar mass:
mass of solute = (moles of solute) × (molar mass of FeCl3)
mass of solute = (0.238 M × 1 L) × (162.20 g/mol)
mass of solute = 38.52 g
Therefore, approximately 38.52 grams of FeCl3 are needed to make a 0.238 M FeCl3 solution in 1000 mL of solution.