A truck of mass 2000kg moving on a highway experiences an average frictional force of 800N. If it's speed increases from 25m/s to 35m/s over a distance of 500m what is the force generated by the truck .
vf^2=vi^2+2ad
but a=netforce/mass
35^2=25^2+2*(Fgenerated-Friction)*d/mass
friction=800N, d=500m
solve for Fgenerated.
To find the force generated by the truck, we can use Newton's second law of motion, which states that the net force acting on an object is equal to its mass multiplied by its acceleration. In this case, we need to determine the acceleration of the truck.
First, let's calculate the change in speed (∆v) of the truck: (∆v) = final velocity - initial velocity = 35 m/s - 25 m/s = 10 m/s.
Next, we need to find the time it takes for the truck to cover the given distance of 500m at an average speed of 30 m/s (midpoint between 25 m/s and 35 m/s):
Time (t) = distance (d) / average speed (v) = 500 m / 30 m/s ≈ 16.67 s.
Now, we can calculate the acceleration (a) of the truck:
Acceleration (a) = ∆v / t = 10 m/s / 16.67 s ≈ 0.6 m/s².
Finally, we can determine the force generated by the truck using Newton's second law:
Force (F) = mass (m) * acceleration (a).
Given that the mass of the truck (m) is 2000 kg, the force generated by the truck is:
Force (F) = 2000 kg * 0.6 m/s² = 1200 N.
Therefore, the force generated by the truck is 1200 N.