area of rectangle is 9 13/18. and the length is 4 3/8.what will be the width ? what will be the perimeter ?
W * L = Area
W * 4 3/8 = 9 13/18
Solve for W.
2W + 2L = perimeter
4 3/8 * w = 9 13/18
35/8 * w = 175/18
9/9 (35/8) * w = 4/4 (175/18)
315 w = 700
w = 140/63 = 2.222...
2.2222 + 4.375 = 6.6
so p = 13.2
To find the width of a rectangle, we can use the formula:
Area = Length × Width
In this case, we are given the area of the rectangle as 9 13/18 and the length as 4 3/8.
First, let's convert the mixed numbers to improper fractions:
9 13/18 = (9 × 18 + 13)/18 = 175/18
4 3/8 = (4 × 8 + 3)/8 = 35/8
Now we can substitute the values into the formula:
Area = Length × Width
175/18 = 35/8 × Width
To isolate the width, we can divide both sides of the equation by 35/8:
(175/18)/(35/8) = Width
175/18 × 8/35 = Width
70/9 = Width
Therefore, the width of the rectangle is 70/9.
To find the perimeter of a rectangle, we can use the formula:
Perimeter = 2 × (Length + Width)
Using the given length of 4 3/8 and the calculated width of 70/9:
Length = 4 3/8 = (4 × 8 + 3)/8 = 35/8
Width = 70/9
Substituting these values into the formula:
Perimeter = 2 × (35/8 + 70/9)
Perimeter = 2 × [(35 × 9 + 70 × 8)/(8 × 9)]
Perimeter = 2 × (315 + 560)/(72)
Perimeter = 2 × 875 / 72
Perimeter = 1750 / 72
To simplify the answer, we can divide the numerator and denominator by their greatest common divisor (GCD), which is 25:
Perimeter = (1750 ÷ 25) / (72 ÷ 25)
Perimeter = 70 / 2.88
So, the approximate perimeter of the rectangle is 24.31.