If I add water to NaNO3 does it make HNO3 and NaOH?
For example
NaNO3 + H2O -> HNO3 + NaOH
is that equation correct?
Please explain if it's not. Thanks!
You have posted this question in the last week or so. It is the same question but has taken many different forms. If we knew what was confusing you we might be able to help. HNO3 + NaOH is an acid/base neutralization that essentially goes to completion from left to right. At the end of the neutralization reaction the rxn is about 99.999 complete; i.e., there is almost no tendency for the reaction to reverse and form HNO3 and NaOH. Most would write NaNO3 + HNO3 ==> no reaction.
Where did NaNO3 + HNO3 come from?
The NaNO3 and H2O came from the acid/base neutralization of HNO3 and NaOH; i.e.,
HNO3 + NaOH ==> NaNO3 + H2O
The reaction I have written is about 99.999% (or more) complete; therefore there is a <0.001% chance that the reverse reaction, which you wrote first, will occur.
The equation you provided, NaNO3 + H2O -> HNO3 + NaOH, is not correct. When you add water to NaNO3 (sodium nitrate), it does not spontaneously react to form HNO3 (nitric acid) and NaOH (sodium hydroxide).
To determine the products of a chemical reaction, it is important to consider the chemical properties and the potential reactions of the compounds involved. In this case, sodium nitrate (NaNO3) is a stable compound that does not readily decompose or react with water to produce nitric acid (HNO3) and sodium hydroxide (NaOH).
To verify the correctness of a chemical reaction, we follow a set of rules called the law of conservation of mass. According to this law, the total mass of the reactants must equal the total mass of the products.
To correctly balance an equation, we need to determine the stoichiometry, which is the ratio of the reactants and products in terms of moles. We can do this by consulting reliable sources, such as chemical databases or literature.
In this case, if we were to balance the equation for the reaction between sodium nitrate and water, it would look like this:
2 NaNO3 + H2O -> 2 NaNO2 + O2
This balanced equation represents the decomposition of sodium nitrate (NaNO3) into sodium nitrite (NaNO2) and oxygen gas (O2) when heated. However, it is worth mentioning that the decomposition of sodium nitrate typically requires high temperatures and is not a spontaneous reaction when simply mixed with water.
Remember, it is always important to research and verify the chemical properties and reactions of the compounds involved before making any assumptions or writing chemical equations.