What is the monomial if a cube of a monomial is:1/8 a^27

To find the monomial if the cube of a monomial is 1/8a^27, we need to take the cube root of 1/8a^27.

Step 1: Simplify 1/8 to get 1/2^3, which is equal to 1/2.

Step 2: Simplify a^27. Since we are taking the cube root, we need to divide the exponent by 3. 27 divided by 3 is 9. Therefore, a^27 simplifies to a^9.

Step 3: Combine the simplified fractions and exponents. The monomial is 1/2a^9. So, the monomial if the cube of a monomial is 1/8a^27 is 1/2a^9.

Try then

(a^9/2)^3 = a^27/ 8

thanks i will

well,

8 = 2^3
a^27 = (a^9)^3
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