-3(×-5y)+1÷2 (4×-10y)
-3(x-5y)+1÷2 (4x-10y)
assuming you mean
-3(x-5y)+1
---------------
2(4x-10y)
that is
(-3x+15y+1)/(8x-20y)
Your syntax is a bit ambiguous.
And where do you get off using the multiply operator (×) for a variable (x)? Seems a lot of trouble.
To simplify the given expression: -3(×-5y) + 1 ÷ 2 (4×-10y), we should follow the order of operations, which is commonly known as PEMDAS (Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction) or BODMAS (Brackets, Orders, Division and Multiplication, and Addition and Subtraction).
Let's break down the expression step by step:
Step 1: Simplify the expression within the parentheses, -3(×-5y):
Multiplying -3 by -5y gives us 15y.
So now the expression becomes: 15y + 1 ÷ 2 (4×-10y).
Step 2: Simplify the expression within the parentheses, 4×-10y:
Multiplying 4 by -10y gives us -40y.
Now the expression becomes: 15y + 1 ÷ 2 (-40y).
Step 3: Evaluate the division, 1 ÷ 2:
The division of 1 by 2 gives us 0.5.
So now the expression becomes: 15y + 0.5 (-40y).
Step 4: Simplify the expression by distributing 0.5 to (-40y):
Multiplying 0.5 by -40y gives us -20y.
Therefore, the simplified expression is: 15y - 20y.
Step 5: Combine like terms:
Since both terms (15y and -20y) have the same variable "y", we can combine them by adding or subtracting their coefficients.
15y - 20y simplifies to -5y.
In conclusion, the simplified expression is -5y.