At a local track meet, RCMS won 3 blue ribbons than red ribbons. They also won 7 more yellow ribbons than red ribbons. RCMS won a total of 28 ribbons. How many of each color did RCMS win?
Let R = red ribbons
R + R + 3 + R + 7 = 28
3R + 10 = 28
3R = 18
R = 6 red ribbons
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To solve this problem, let's assume the number of red ribbons won by RCMS is "x."
According to the problem, RCMS won 3 blue ribbons more than red ribbons. Therefore, the number of blue ribbons won by RCMS would be "x + 3."
Additionally, RCMS won 7 more yellow ribbons than red ribbons. This means the number of yellow ribbons won by RCMS would be "x + 7."
The total number of ribbons won by RCMS is given as 28. So, we can set up the equation:
x + (x + 3) + (x + 7) = 28
Now, let's solve the equation:
3x + 10 = 28
Subtracting 10 from both sides:
3x = 18
Dividing both sides by 3:
x = 6
Therefore, RCMS won 6 red ribbons, 9 blue ribbons (6 + 3), and 13 yellow ribbons (6 + 7).